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i=1 →dσ11dx1+dσ21dx2+dσ31dx3+F1=0

-F2= -1,010 + 1,810x32 - 0,210·2·x3=

-1,010 + 1,810·(-1,710)2 - 0,210·2·(-1,710) = 5,008MN/m3

→ F2 = - 5,0008MN/m3

i=2 →dσ12dx1+dσ22dx2+dσ32dx3+F2=0

i=3 →dσ13dx1+dσ23dx2+dσ33dx3+F3=0

ε11=du1dx1, ε12=ε21=12du2dx1+du1dx2, ε32=ε23=12du3dx2+du2dx3, ε22=du2dx2,

ε32=12du3dx2+du2dx3=121,310x1-0,510x1∙2x3=121,310∙0,110-0,510∙0,110∙2∙5,990=-0,2640·10-4

(2,020 - σ2)·(-2,230 - σ2)·(-6,060 - σ2) – 3,0302·(-2,230 - σ2)=0 → σ2=-2,230 ˅ σ2=3,030 ˅ σ2=-7,070

9,09 n1+ 3,03 n3=0 → n1= -0,333n3

n12+ n22+ n32=1 → (-0,333n3)2...