P27_066.PDF

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Chapter 27 - 27.66
66. Assuming J is directed along the wire (with no radial flow) we integrate, starting with Eq. 27-4,
i =
J
dA = R
R/ 2
3 kπ R 3
−
R 3
8
where k =3 . 0
×
10 8 and SI units understood. Therefore, if R =0 . 00200 m, we obtain i =4 . 40 A.
kr 2 πr dr = 2

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