P16_006.PDF

(64 KB) Pobierz
Chapter 16 - 16.6
6. (a) Hooke’s law readily yields k = (15kg)(9 . 8m / s 2 ) / (0 . 12m) = 1225N / m. Rounding to three signifi-
cant figures, the spring constant is therefore 1 . 23 kN/m.
(b) We are told f =2 . 00Hz = 2 . 00cycles / sec. Since a cycle is equivalent to 2 π radians, we have
ω =2 π (2 . 00) = 4 π rad/s (understood to be valid to three significant figures). Using Eq. 16-12, we
find
m = 1225N / m
(4 π rad / s) 2 =7 . 76 kg .
Consequently, the weight of the package is mg =76N.
ω = k
m
=
643284502.001.png
Zgłoś jeśli naruszono regulamin