p19_059.pdf

(69 KB) Pobierz

Chapter 19 - 19.59

59. (a) Recalling that a change in Kelvin temperature is numerically equivalent to a change on the Celsius

scale, we ﬁnd that the rate of heat conduction is

P cond = kA ( T H −

T C )

= (401W / m

K)(4 . 8

10 − 4 m 2 )(100C ◦ )

1 . 2m

=16 J / s .

(b) Using Table 19-4, the rate at which ice melts is

= P cond

L F

= 16J / s

333J / g =0 . 048 g / s .