Zad2b.pdf

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Mathcad - zadanie2b.mcd
Zadanie 2b Transformator 24 MVA, 110/30 kV/kV obliczenia na napieciu 110 kV
R/2 X/2
R/2 X/2
U 1
G
B
R 1.48
X 21.9
:=
i
:=
i
G 6.6 10
⋅
−
6
B 61.5 10
:=
⋅
−
6
U2 110 10 3
:=
⋅
U2 1.1 10 5
=
×
P2 19 10 6
:=
⋅
Q2 8 10 6
:=
⋅
S2 P2 2
:=
+
Q2 2
S2 2.0616 10 7
=
×
I2
:=
S2
3 U2
I2 108.2035
⋅
cosfi2
:=
P2
S2
cosfi2 0.9216
=
I2cz I2 cosfi2
:=
⋅
I2cz 99.7241
=
I2b sign Q()
:=
−
I2 2
−
I2cz 2
I2b 41.9891
=
−
I2zesp I2cz I2b i
:=
+
⋅
I2zesp 99.7241 41.9891i
=
−
U2zesp U2
:=
Z2zesp R X i
:=
+
⋅
Z2zesp 1.48 21.9i
=
+
UZ2zesp Z2zesp I2zesp
:=
⋅
UZ2zesp 1.0672 10 3
=
× 2.1218i 1
+
×
UZ2 UZ2zesp
:=
UZ2 2.3751 10 3
=
×
:=
:=
=
96289286.009.png 96289286.010.png 96289286.011.png 96289286.012.png 96289286.001.png
UGBzesp U2zesp 3 UZ2zesp
:=
+
⋅
UGBzesp 1.1185 10 5
=
× 3.6751i 10 3
+
×
UGB UGBzesp
:=
UGB 1.1191 10 5
=
×
Yzesp G B i
:=
−
⋅
Yzesp 6.6 10
=
×
−
6
−
6.15i 10
×
−
5
IYzesp
:=
UGBzesp
3
Yzesp
IYzesp 0.5567 3.9574i
=
−
I1zesp I2zesp IYzesp
:=
+
I1zesp 100.2808 45.9465i
=
−
I1 I1zesp
I1 110.3056
=
Z1zesp R X i
:=
+
⋅
Z1zesp 1.48 21.9i
=
+
UZ1zesp I1zesp Z1zesp
:=
⋅
UZ1zesp 1.1546 10 3
=
× 2.1281i 10 3
+
×
U1zesp UGBzesp 3 UZ1zesp
:=
+
⋅
U1zesp 1.1385 10 5
=
× 7.3612i 10 3
+
×
U1 U1zesp
:=
U1 1.1409 10 5
=
×
PR1 3 I1 2
:=
⋅ R
⋅
PR1 5.4023 10 4
=
×
QX1 3 I1 2
:=
⋅ X
⋅
QX1 7.9939 10 5
=
×
PG UGB 2 G
⋅
PG 8.2656 10 4
=
×
QB UGB 2 B
⋅
QB 7.702 10 5
=
×
PR2 3 I2 2
:=
⋅ R
⋅
PR2 5.1983 10 4
×
QX2 3 I2 2
:=
⋅ X
⋅
QX2 7.6921 10 5
×
P1 P2 PR1
+
+
PR2
+
PG
P1 1.9189 10 7
=
×
Q1 Q2 QX1
+
+
QX2
+
QB
Q1 1.0339 10 7
=
×
cosf1
:=
P1
P1 2
cosf1 0.8803
=
Q1 2
+
⋅
:=
:=
:=
=
=
:=
:=
96289286.002.png 96289286.003.png 96289286.004.png 96289286.005.png 96289286.006.png 96289286.007.png
 
U2w
:=
⎝
+
U2zesp
⎞
⎠
U1w
:=
⎝
+
U1zesp
⎞
⎠
UZw
:=
⎝
U1zesp
U2zesp
⎞
⎠
8000
6000
Im U2w
(
)
Im U1w
(
)
4000
Im UZw
(
)
2000
0
2 . 10 4
4 . 10 4
6 . 10 4
8 . 10 4
1 . 10 5
1.2 . 10 5
0
Re U2w
) Re U1w
,
(
)
,
Re UZw
(
)
0i
0i
(
96289286.008.png

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