p44_041.pdf
(
54 KB
)
Pobierz
Chapter 44 - 44.41
41. (a) From
ρ
H
=0
.
35
ρ
=
n
p
m
p
,wegettheprotonnumberdensity
n
p
:
n
p
=
0
.
35
ρ
m
p
=
(0
.
35)(1
.
5
×
10
5
kg
/
m
3
)
=3
.
14
×
10
31
m
−
3
.
1
.
67
×
10
−
27
kg
(b) From Chapter 20 (see Eq. 20-9), we have
N
V
=
p
kT
=
1
.
01
10
−
23
J
/
K)(273 K)
=2
.
68
×
10
5
Pa
×
10
25
m
−
3
(1
.
38
×
for an ideal gas under “standard conditions.” Thus,
(
N/V
)
=
3
.
14
n
p
×
10
25
m
−
3
=1
.
2
×
10
6
.
2
.
44
×
10
31
m
−
3
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