p42_006.pdf
(
46 KB
)
Pobierz
Chapter 42 - 42.6
6. We note that there is one conduction electron per atom and that the molar mass of gold is 197 g
/
mol.
Therefore, combining Eqs. 42-2, 42-3and 42-4 leads to
n
=
(19
.
3g
/
cm
3
)(10
6
cm
3
/
m
3
)
(197 g
/
mol)
/
(6
.
02
10
23
mol
−
1
)
=5
.
90
×
10
28
m
−
3
.
×
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