p40_021.pdf

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Chapter 40 - 40.21
21. (a) and (b) Schrodinger’s equation for the region x>L is
d 2 ψ
dx 2
+ 8 π 2 m
h 2
[ E
U 0 ] ψ =0 ,
U 0 < 0. If ψ 2 ( x )= Ce 2 kx ,then ψ ( x )= C e −kx ,where C is another constant satisfying
C 2 = C .Thus d 2 ψ/dx 2 =4 k 2 C e −kx =4 k 2 ψ and
d 2 ψ
dx 2
+ 8 π 2 m
h 2
[ E
U 0 ] ψ = k 2 ψ + 8 π 2 m
h 2
[ E
U 0 ] ψ.
This is zero provided that
k 2 = 8 π 2 m
h 2
[ U 0
E ] .
The quantity on the right-hand side is positive, so k is real and the proposed function satisfies
Schrodinger’s equation. If k is negative, however, the proposed function would be physically unre-
alistic. It would increase exponentially with x . Since the integral of the probability density over the
entire x axis must be finite, ψ diverging as x
→∞
would be unacceptable. Therefore, we choose
k = 2 π
h 2 m ( U 0
E ) > 0 .
where E
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