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Chapter 19 - 19.26

26. We use Q = cm ∆ T . The textbook notes that a nutritionist’s “Calorie” is equivalent to 1000 cal. The

mass m ofthe water that must be consumed is

m =

c ∆ T =

3500

10 3 cal

=94 . 6

10 4 g ,

(1 g / cal

C ◦ )(37 . 0 ◦ C

−

0 . 0 ◦ C)

which is equivalent to 9 . 46

10 4 g / (1000 g / liter) = 94 . 6 liters ofwater. This is certainly too much to

drink in a single day!