p11_103.pdf

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Chapter 11 - 11.103

103. The problem asks us to assume v com and ω are constant. For consistency of units, we write

v com =(85mi / h) 5280 ft / mi

60 min / h

Thus, with ∆ x = 60 ft, the time of ﬂight is t =∆ x/v com =60 / 7480 = 0 . 00802 min. During that time,

the angular displacement of a point on the ball’s surface is

θ = ωt = (1800 rev / min)(0 . 00802 min)

≈

14 rev .

= 7480 ft / min .