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Chapter 11 - 11.7

7. Applying Eq. 2-15 to the vertical axis (with + y downward) we obtain the free-fall time:

∆ y = v 0 y t + 1

⇒

t = 2(10)

9 . 8

=1 . 4s .

Thus, by Eq. 11-5, the magnitude ofthe average angular velocity is

ω avg =

(2 . 5)(2 π )

1 . 4

=11rad / s .

2 gt 2