p05_046.pdf

46. We write the length unit light-month as c

month in this solution.

(a) The magnitude of the required acceleration is given by

a = ∆ v

∆ t =

10 8 m / s)

(3 . 0days)(86400s / day) =1 . 2

10 2 m / s 2 .

(b) The acceleration in terms of g is

a = a

g = 1 . 2

10 2 m / s 2

9 . 8m / s 2

g =12 g.

F = ma = 1 . 20

10 6 1 . 2

10 2 =1 . 4

10 8 N .

month during one month. The time it takes for the

spaceship to travel at constant speed for 5 . 0light-months is

t = d

v = 5 . 0c

months

0 . 1 c

=50months

which is about 4 . 2years.

(0 . 10)(3 . 0

(d) The spaceship will travel a distance d =0 . 1 c