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Basic principles of celestial navigation
James A. Van Allen
a)
Department of Physics and Astronomy, The University of Iowa, Iowa City, Iowa 52242
~
Received 16 January 2004; accepted 10 June 2004
!
Celestial navigation is a technique for determining one’s geographic position by the observation of
identified stars, identified planets, the Sun, and the Moon. This subject has a multitude of
refinements which, although valuable to a professional navigator, tend to obscure the basic
principles. I describe these principles, give an analytical solution of the classical two-star-sight
problem without any dependence on prior knowledge of position, and include several examples.
Some approximations and simplifications are made in the interest of clarity. ©
2004 American
Association of Physics Teachers.
@
#
I. INTRODUCTION
is between 0° and 360°, although often it is
convenient to take the longitude westward of the prime me-
ridian to be between 0° and
L
Celestial navigation is a technique for determining one’s
geographic position by the observation of identified stars,
identified planets, the Sun, and the Moon. Its basic principles
are a combination of rudimentary astronomical knowledge
and spherical trigonometry.
1–3
Anyone who has been on a ship that is remote from any
terrestrial landmarks needs no persuasion on the value of
celestial navigation. There are modern electronic naviga-
tional aids such as Loran, ocean bottom soundings, and the
global positioning system
180°. The longitude of
P
also
can be specified by the plane angle in the equatorial plane
whose vertex is at
O
with one radial line through the point at
which the meridian through
P
intersects the equatorial plane
and the other radial line through the point
G
at which the
prime meridian intersects the equatorial plane
2
~
see Fig. 1
!
.
III. THE CELESTIAL SPHERE
which depends on receiving
precise timing data from a world-wide network of artificial
satellites, each carrying one or more atomic clocks. This pa-
per illustrates what can be learned with only a sextant, rudi-
mentary astronomical tables, and an accurate knowledge of
absolute time
~
GPS
The celestial sphere is an imaginary spherical surface
whose radius is very much greater than that of the Earth,
with its center at
O
and its polar axis coincident with the
Earth’s rotational axis. The position of each celestial object is
represented by the point on the celestial sphere at which a
line to it from
O
intersects this sphere. Inasmuch as the dis-
tances to all stars, planets, and the Sun are much greater than
the radius of the Earth, a terrestrial observer may be thought
of as viewing the sky from
O
. For the nearby Moon, how-
ever, its apparent position on the celestial sphere is, because
of parallax, different by as much as nearly one degree for
observers at different latitudes and longitudes.
8
It is impos-
sible to make an
a priori
correction for this effect if the
observer’s position is initially unknown.
On the celestial sphere, the declination
.
It is intended for students who are curious about the basic
principles of celestial navigation and makes no pretense of
serving a professional navigator or surveyor.
~
from radio signals or a precise chronometer
!
II. THE EARTH AND GEOGRAPHIC POSITION
The surfaces of the land masses of the Earth and of the
oceans are approximated as the surface of a spherically sym-
metric body of unit radius, hereafter called the terrestrial
sphere.
4
The Earth as a whole is assumed to be rotating at a
constant angular velocity about an inertially oriented axis
through its geometric center
O
. A geographic position
P
is
referenced to a right-hand spherical coordinate system whose
center is at
O
and whose positive
Z
-axis is coincident with
the Earth’s rotational axis and in the same sense as the
Earth’s angular momentum vector. The plane through
O
that
is perpendicular to this axis is called the equatorial plane
d
of a celestial
of a terrestrial
observer as defined in the above. The second spherical coor-
dinate of a celestial object, called right ascension
F
,isthe
dihedral angle analogous to eastward terrestrial longitude,
but with the fundamental difference that it is measured from
a different reference point. That reference point on the celes-
tial equator is called the vernal equinox, usually denoted by
g
a
~
the
, and defined as follows. The equatorial plane of the Earth
is tilted to the plane of its orbit
. Any plane that contains the rotational axis in-
tersects the spherical surface in a great circle called a merid-
ian. By convention, the
X
axis lies in the meridian plane
!
about the
Sun by 23.44°. These two planes intersect along a line that
pierces the celestial sphere at two points, called nodes. The
vernal equinox is the ascending node of the ecliptic on the
equator, that is, the position of the Sun on or about 21 March
of each year as the Sun ascends from southerly to northerly
declination. The right ascension
~
the ecliptic plane
!
~
the
prime meridian
!
that passes through a point in Greenwich,
England.
1
The position
P
is specified by two coordinates, its latitude
. The latitude is the plane angle whose
apex is at
O
, with one radial line passing through
P
and the
other through the point at which the observer’s meridian in-
tersects the equator. Northern latitudes are taken to be posi-
tive
and longitude
L
of a celestial object, al-
ways taken to be positive eastward, is measured from the
vernal equinox. Astronomers usually measure right ascension
in hours, minutes, and seconds of time, but it can be con-
verted to the equivalent angular measure by taking one hour
5
a
.
The longitude is the dihedral angle,
3,5–7
measured eastward
from the prime meridian to the meridian through
P
. The
~
0° to 90°
!
and southern latitudes negative
~
0° to
2
90°
!
15°. Another commonly used quantity is called the hour
angle. It is the dihedral angle between any specified meridian
1418
Am. J. Phys.
72
~
11
!
, November 2004
http://aapt.org/ajp
© 2004 American Association of Physics Teachers
1418
DOI: 10.1119/1.1778391
longitude
!
object is strictly analogous to the latitude
X
–
Y
plane
F
Fig. 3. Definition of the zenith distance
z
of a star or other celestial object.
IV. OBSERVATIONAL CONSIDERATIONS
. The celestial
sphere rotates westward from the observer’s point of view at
an angular rate such that the vernal equinox transits
F
and longitude
L
Fig. 1. Definition of latitude
F
and longitude
L
.
~
a
!
Meridian cross-section
of the Earth through the observer at
P
. The center of the Earth is at
O
and
NP and SP are the north pole and south pole, respectively.
~
b
!
Equatorial
cross-section of the Earth.
G
represents the point at which the prime merid-
ian through Greenwich intersects the equator and
P
represents the point at
which the meridian through
P
intersects the equator.
E
means eastward and
W
means westward. The longitude
L
is the dihedral angle
~
Ref. 7
!
between
the two named meridian planes, but is more easily visualized in this equa-
torial diagram.
~
passes
the observer’s meridian from east to west at inter-
vals of 23 hour, 56 minute, 4 second of mean solar time, also
called the sidereal rotational period of the Earth or the side-
real day.
The observer’s zenith is defined by the outward extension
of the line from the center of the Earth through the observer
as in Fig. 3. The instantaneous angle between the observer’s
zenith and the line to a star is called the star’s zenith distance
and is denoted by
!
plane and the meridian plane through a celestial object, al-
ways taken to be positive westward and lying in the range
0–24 h or 0°–360°. The sidereal hour angle
z
. As the celestial sphere rotates westward
that is, clockwise as viewed from above the
north celestial pole
~
of a
celestial object, taken to be positive westward from the ver-
nal equinox, is related to the right ascension
~
SHA
!
decreases from 90° as the star rises
from below the observer’s eastern horizon, has a minimum
value
!
,
z
~
Fig. 2
!
by
z
min
as
S
crosses the observer’s meridian, then in-
creases to 90° as the star sets below the observer’s western
horizon. These comments are applicable to all celestial ob-
jects for which
SHA
5
360°
2a
.
~
1
!
We will take
a
,
d
, and the SHA to be fixed quantities for any
. Stars whose declinations meet
this condition transit the observer’s meridian at intervals of
exactly one sidereal day; but the intervals between the suc-
cessive transits of planets, the Sun and the Moon vary, al-
though predictably.
Stars for which
d,~
90°
2F!
beyond the solar sys-
tem; however, they vary with time for the planets, the Sun,
and the Moon. Their values are tabulated in almanacs,
9–11
of
which
The Air Almanac
9
~
for example, stars or galaxies
!
is the most convenient for a navi-
gator.
constitute the observer’s cir-
cumpolar star field which, as viewed from
O
or any point on
the Earth, rotates counterclockwise for a northern hemi-
sphere observer or clockwise for a southern hemisphere ob-
server as time progresses. Such stars neither rise nor set,
being always above the observer’s horizon as they move
along small circles centered on the celestial pole. Their ze-
nith distances have a maximum value of 180°
d>~
90°
2F!
2~F1d!
at
at
upper culmination as they transit the observer’s meridian
twice per sidereal day.
Usually, a practitioner of celestial navigation employs a
marine sextant or an aircraft bubble sextant to determine the
instantaneous altitude of a celestial object, the vertical angle
of the object above the local horizontal plane. After appro-
priate corrections,
1,2
this quantity is denoted by
h
. However,
because of its simpler geometrical significance, I prefer the
zenith distance
~F2d!
or
~d2F!
Fig. 2. Right ascension
~a!
and sidereal hour angle
~
SHA
!
are both dihedral
angles
~
Ref. 7
!
measured from the meridian plane through the vernal equi-
nox
g
, with
a
positive eastward and SHA positive westward. In this equa-
torial diagram,
S
represents the intersection of the meridian plane through a
star or any other celestial object with the equator.
z
to represent the observed quantity, with
1419
Am. J. Phys., Vol. 72, No. 11, November 2004
James A. Van Allen
1419
Imagine that a terrestrial observer is located at a fixed
point
P
of unknown latitude
through
about the Earth
object
lower culmination and a minimum value
Fig. 4.
P
represents the position of the observer and
S
the position of the
substellar point of a star at the moment that it transits the observer’s merid-
ian.
O
is the center of the Earth,
d
the declination of the star,
F
the latitude
of the observer, and
z
the zenith distance of the star. NP is the north pole and
SP is the south pole.
Fig. 5. Cross-section of the terrestrial sphere in any plane containing the line
from the center of the Earth
O
through a substellar point
S
. The circle of
position is the intersection with the sphere of the circular cone whose axis is
OS
and whose half-angle is
z
, the zenith distance of the star. The dashed line
represents an edge-on view of the plane containing the circle of position.
The normal to this plane through
O
has length
OR
5
p
.
is the zenith distance of Polaris, and, at this level of
approximation, is constant and independent of the time of
day. Hence, Polaris has had a special simplicity for determin-
ing latitude throughout maritime history. For example, a ves-
sel can sail from Europe to America without an accurate
knowledge of the time by simply maintaining a westerly
course during which
z
z5
90°
2
h
.
~
2
!
is treated as intrinsically positive and is in the
range 0° to 90°.
z
V. DETERMINATION OF LATITUDE BY MERIDIAN
TRANSIT OF A STAR
of Polaris is approximately constant or
changes day-by-day in such a way as to assure landfall in
America at approximately an intended latitude. Because the
diurnal motion of Polaris lies along a small circle around the
north celestial pole of angular radius 0.73°, an improvement
in accuracy in determining the latitude is to observe Polaris
at specific moments identified from its ephemeris.
10,11
z
As illustrated in Fig. 4,
F5d1z
min
,
~
3
!
At
where
F
is the observer’s latitude,
d
is the declination of the
lower culminations
F5
90.73°
2z
, at upper culminations
z
min
is the observed minimum value of the zenith
distance of the star
F5
89.27°
2z
, and at maximum eastern or western elonga-
~
a southerly angle in this example
!
as it
. Also the observation of Polaris provides a
convenient method for determining true north. Unfortunately,
there is no comparably bright star in the near vicinity of the
south celestial pole.
2
Note that on the terrestrial sphere, one arcminute
F5
90°
2z
transits the observer’s meridian.
If the star transits the observer’s meridian northward of
P
,
the corresponding relation is
F5d2z
min
.
~
4
!
~
1
8
!
of
corresponds to a north–south distance of one nau-
tical mile or 6080 ft
F
z
min
is zero at
the moment that the object transits the observer’s meridian,
that is, at the observer’s zenith. Thus, in this special case, the
observer’s latitude is equal to the declination of the star.
The same considerations are applicable to determining
latitude by observing the meridian transit of planets or the
center point of the disk of the Sun. But stars are conceptually
simpler because their values of
d5F
, the value of
~
easily remembered as ‘‘a mile a
minute’’
!
, whereas one arcminute of longitude
L
corresponds
to cos
F
nautical mile.
are almost constant,
whereas these coordinates for all celestial objects of the solar
system have changing values of
a
and
d
VII. DETERMINATION OF LONGITUDE AND
LATITUDE BY OBSERVATION OF TWO OR MORE
STARS
a
and
d
which must be taken
z
1
of a star has been
observed at a particular time. It is evident from Fig. 5 that
the same value of
from a daily ephemeris.
9
In any case, an observer also obtains the ‘‘true north’’ or
‘‘true south’’ direction, namely the direction of any celestial
object at the moment of its upper or lower culmination.
would have been observed simulta-
neously at an infinite number of other points on a small
circle, called the ‘‘circle of position,’’ on the terrestrial
sphere. This circle is the intersection with the sphere of a
circular cone having its vertex at the center of the Earth, half
angle
z
VI. DETERMINATION OF LATITUDE BY
OBSERVING POLARIS
, and its axis through the substellar point
S
, the point
on the terrestrial sphere at which the line from
O
to the star
pierces that sphere.
Next, suppose that the zenith distance
z
An especially valuable star for northern hemisphere navi-
gators is the bright star Polaris
~
the North Star or
a
Ursa
z
2
of a second star
is observed simultaneously. This observation defines a sec-
ond small circle on the terrestrial sphere. The plane contain-
ing the circle of position for star 1 and the one containing the
circle of position for star 2 intersect in a line through
P
and
P
Minoris
!
which presently has declination
d51
89.27°. Thus,
the observer’s latitude
F
is approximately equal to the alti-
tude of Polaris or
F'
90°
2z
,
~
5
!
8
~
see Fig. 6
!
. The observer’s latitude is that of either point
1420
Am. J. Phys., Vol. 72, No. 11, November 2004
James A. Van Allen
1420
where
The quantity
star, and
tions,
latitude
For a celestial object having
Suppose that the zenith distance
l5
360°
2
GHA
*
.
~
7
!
plus the GHA* for each observed
star complete the basic data set required for determination of
the latitude and longitude of the observer.
z
The word ‘‘star’’
is used for convenience in this and other sections, but the
analysis is equally applicable to any celestial body,
~
~
except
the Moon, as noted above
!
given its instantaneous values of
.
The following solution of the two-star-sight problem is
adapted from Ref. 13. Figure 6 depicts two intersecting
circles of position on the terrestrial sphere. A unique position
of the observer occurs in the special case of either internal or
external tangency of the two circles. But, in general the
circles intersect at two points
P
and
P
and GHA
!
Fig. 6. In this sketch of the terrestrial sphere,
S
1and
S
2 are the simulta-
neous geographic positions of the respective substellar points of star 1 and
star 2. The two circles of position correspond to the observed zenith dis-
tances of the two stars and intersect at points
P
and
P
8
, the two possible
geographic positions of the observer.
. Each circle is the
intersection of a circular cone of half angle
8
with the terres-
trial sphere of radius unity, or otherwise stated, the inter
sec-
tion of the sphere with a plane perpendicular to the line
OS
from the center of the sphere
O
through the substellar point
S
and at a normal distance
p
from
O
z
. Auxiliary information can make possible the
choice between usually widely separated points
P
and
P
8
8
.If
.InFig.5itis
noted that a line from any point on the terrestrial spher
e to
the identified star on the celestial sphere is parallel to
OS
~
~
see Fig. 5
!
z
3
of a
third star resolves the twofold ambiguity and provides a
unique choice between
P
and
P
.
The resulting position is referenced to the substellar points
of the stars at the moment of observation. But these points
move progressively westward as the celestial sphere rotates
and the derived position of the observer also moves progres-
sively westward at the known, constant latitude, that is,
along a small circle on the terrestrial sphere in a plane par-
allel to the equator.
To determine the longitude
8
that is, zero parallax
.
The equation of the plane containing a circle of position
!
is
6
!
where
l
,
m
, and
n
are the angles to the geographic
X
,
Y
, and
Z
axes. respectively. of the normal to the plane through
O
;
p
is the length of the normal
O
W
~
x
cos
l
1
y
cos
m
1
z
cos
n
2
p
5
0,
~
8
of the observer, a knowledge
of the simultaneous longitudes of the respective substellar
points is essential. In other words, it is essential to know the
absolute time
L
see Fig. 5
!
. Also
p
5
cos
z
,
~
9
!
~
for example, GMT, the mean solar time at
and
. The historical challenge of developing an accu-
rate chronometer for maritime use rests on this simple fact.
12
Truly simultaneous observations of stars may not be fea-
sible in practice. But we make this assumption so as to
present the basic geometric principle. Suppose that the ob-
server has made simultaneous observations of the zenith dis-
tances of two
!
n
5
90
2d
.
~
10
!
Let
a
[
cos
l
5
cos
l
cos
d
,
~
11a
!
b
[
cos
m
5
sin
l
cos
d
,
~
11b
!
stars at a particular moment, as de-
scribed above, and that the GMT of the moment of
observation also has been recorded.
It is usual to specify the hour angle of the ‘‘mean Sun’’
relative to the prime meridian as GMT or Universal Time
~
~
or more
!
c
[
cos
n
5
sin
d
,
~
11c
!
p
5
cos
z
.
~
11d
!
In terms of the known quantities
z
,
d
, and
l
, the equation of
. The mean Sun is a fictitious point on the celestial
equator that moves eastward on the celestial sphere at a con-
stant rate so as to match the yearly average, or mean, rate of
the actual Sun.
The definition of a Greenwich hour angle
!
each plane is
a
i
x
1
b
i
y
1
c
i
z
2
p
i
5
0,
~
12
!
with
i
5
1 for one of the planes and
i
5
2 for the other. The
is the
dihedral angle measured westward from the prime meridian
to any other specified meridian. The Greenwich Sidereal
Time
~
GHA
!
two planes intersect along a line
PP
8
, given by the simulta-
neous solution of Eq.
~
12
!
for
i
5
1, 2. The result is
is the instantaneous Greenwich hour angle of
the vernal equinox, GHA
~
GSiT
!
x
5
2
Bz
1
C
5
2
Ey
1
F
,
~
13
!
, which increases at the rate of
360° in 23 hour 56 minute 4 second
g
A
D
~
the sidereal rotational
where
A
or 15.04108° per mean solar hour. The
values of the GHA and
!
for the real Sun, the Moon, and
selected planets are tabulated at 10 min intervals for each day
of the year together with interpolation tables in Ref. 9.
The Greenwich Hour Angle of a celestial object, GHA*,is
given by
GHA*
5
GHA
g1
SHA*.
d
[~
a
1
b
2
2
a
2
b
1
!
,
~
14a
!
B
[
~
b
2
c
1
2
b
1
c
2
!
,
~
14b
!
C
[
~
b
2
p
1
2
b
1
p
2
!
,
~
14c
!
D
[
~
a
1
c
2
2
a
2
c
1
!
,
~
14d
!
!
The corresponding substellar point on the terrestrial sphere is
located at latitude
~
6
E
[
~
b
1
c
2
2
b
2
c
1
!
,
~
14e
!
d
and east longitude
l
, where
F
[
~
c
2
p
1
2
c
1
p
2
!
.
~
14f
!
1421
Am. J. Phys., Vol. 72, No. 11, November 2004
James A. Van Allen
1421
The observed value of
d
P
or point
P
not, simultaneous observation of the zenith distance
Greenwich
UT
period of the Earth
,
x
may be regarded as the parameter that desig-
nates a general point on the line
¯
P
~
13
!
and
y
and
z
are the
other two coordinates of the point. For any
x
, we have
8
y
5
F
2
Dx
E
,
~
15a
!
z
5
C
2
Ax
.
~
15b
!
B
are
the intersections of the above line with the unit sphere; that
is, they are the two points for which
x
2
The two possible positions of the observer
P
and
P
8
1
y
2
1
z
2
5
1.
~
16
!
yields a quadratic
equation for
x
with two real roots
x
p
and
x
p
~
15
!
into Eq.
~
16
!
Fig. 7. GHA
g
, SHA
*
, GHA
*
,
a
and
l
are all dihedral angles
~
Ref. 7
!
as
defined in Secs. II and III. Their relationships are most simply represented
by this diagram of the equatorial plane in which
g
is the vernal equinox,
G
is the intersection of the Greenwich meridian with the equator, and
S
is the
intersection of the meridian through the star with the equator.
8
. The corre-
sponding values of
y
p
and
z
p
and
y
p
and
z
p
are calculated
8
8
by Eq.
~
15
!
to define the two possible positions
P
(
x
p
,
y
p
,
z
p
)
and
P
).
Finally, the latitude
8
(
x
p
,
y
p
,
z
p
8
8
8
are
calculated from the Cartesian coordinates
x
,
y
, and
z
by the
relations
F
and longitude
L
,of
P
and
P
8
sumed position, based on dead reckoning or other approxi-
mate information. The distinctive feature of the present
solution is that it obviates the need for such prior knowledge.
z
tan
F5
y
2
,
~
17a
!
A
x
2
1
VIII. NOTES ON PRACTICALITY
tan
L5
y
x
,
~
17b
!
The use of a marine sextant requires simultaneous visibil-
ity of the celestial object and the local horizon, that is, at
least partially clear skies and twilight conditions for stars and
planets or daylight conditions for the Sun. Under favorable
conditions at sea a skilled observer can determine
).
Recall that the input data for the above analytical solution
are as follows.
F
p
,
L
p
) and
P
8
(
F
p
8
,
L
p
8
to an
accuracy of about one arcminute or better. A bubble aircraft
sextant provides an artificial horizon and greatly expands the
opportunities for observation, although usually with lesser
accuracy than that provided by a marine sextant. Observa-
tion, when practical, of a given celestial object at intervals
of, say, a few hours is equivalent to the two-star-sight tech-
nique, although movement of the observer between observa-
tions must be taken into account.
It should be mentioned that the simultaneous observation
of the zenith distance and azimuth of a single celestial object
at a given GMT, as is possible with a pier-mounted theodo-
lite at a fixed point, yields both
z
z
2
, the simul-
taneously observed zenith distances of the two stars and the
observer’s Greenwich Mean Time of the stellar observations.
~
~
a
!
From the observer:
z
1
and
b
!
Derived from Ref. 9: the values of the longitude
l
1
and
d
1
for the substellar point of star 1 and the longitude
l
2
and the latitude
d
2
for the substellar point of star 2, both
at the GMT of the observations.
The above analytical solution is too tedious to be per-
formed by hand by a practicing navigator, but it can be easily
programmed for a computer of modest capability. The time-
independent values of the latitudes
d
2
of the two
substellar points are taken from standard tables
9,10
d
1
and
. The solution of the
corresponding geometric problem is straightforward, but is
not within the scope of this paper. Note that an error in GMT
of four seconds of time is equivalent to an error of one arc-
minute of longitude.
L
and
F
and the
time-dependent values of their longitudes
l
1
and
l
2
are
given by
l5
360°
2
GHA
*
~
18a
!
or
IX. SOME EXAMPLES
l5
360°
2~
SHA*
1
GHA
g !
.
~
18b
!
A.
F
by meridian transit
In Eq.
~
18b
!
SHA* and GHA
g
are found
~
with interpolation
In a sequence of twilight observations, an observer
finds that the minimum value of the northerly zenith distance
~
~
1
!
if necessary
!
from Ref. 9 for the observer’s recorded GMT
~
Fig. 7
.
The observer then enters the values of
!
that is, at meridian transit
!
of the bright star Vega,
z
min
z
1
,
d
1
, and
l
1
and
5
25.51°. From tables, the declination of Vega
d51
38.38°.
z
2
,
d
2
, and
l
2
, into the computer, which yields
L
p
,
F
p
,
Hence, the observer’s latitude is given by Eq.
~
4
!
, namely,
is the
desired solution, the process is repeated for another pair of
stars, say, 1 and 3. Note that the method is the same for any
practical combination of stars, planets, and the Sun.
The traditional practice
1,2
of celestial navigation uses ob-
servations to refine the observer’s position relative to an as-
, and
F
p
. If it is not obvious whether
P
or
P
8
8
8
F5
38.38°
2
25.51°
51
12.87°.
~
19
!
In a sequence of twilight observations, an observer
finds the minimum zenith distance of Polaris
~
2
!
~
at upper cul-
mination
!
to be
z
min
5
42.15°. The declination of Polaris is
d5
89.27°. Hence,
1422
Am. J. Phys., Vol. 72, No. 11, November 2004
James A. Van Allen
1422
In Eq.
The substitution of Eq.
with attention to resolving quadrant ambiguity, to yield the
desired results: P (
latitude
L
p
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